An object with a mass of #6 kg# is revolving around a point at a distance of #2 m#. If the object is making revolutions at a frequency of #15 Hz#, what is the centripetal force acting on the object?

1 Answer
Jan 22, 2016

Answer:

#108pi^2color(white)(x)"N"#

Explanation:

Centripetal force is given by:

#F=(mv^2)/r#

To find #v:#

#f=15"Hz"#

So the time period #T# is given by:

#T=1/f=1/15s#

#:.v=(2pir)/(1/15)=30pir#

#:.F=(6xx(3pir)^2)/r#

#F=(6xx9pi^2r^(cancel2))/cancel(r)#

#F=54pi^(2)xx2=108pi^(2)color(white)(x)"N"#