# An object with a mass of 6 kg is revolving around a point at a distance of 8 m. If the object is making revolutions at a frequency of 1 Hz, what is the centripetal force acting on the object?

$F = m {\omega}^{2} r = 6 \cdot {\left(2 \pi\right)}^{2} \cdot 8 = 1895$ $N$.
In a linear frame the centripetal force is described as $F = \frac{m {v}^{2}}{r}$ and in a rotational frame as $F = m {\omega}^{2} r$ where $\omega$ is measured in radians.
$1$ $H z$ is $2 \pi$ $r a {\mathrm{ds}}^{-} 1$, so $F = 6 \cdot {\left(2 \pi\right)}^{2} \cdot 8 = 1895$ $N$.