An object with a mass of #6 kg# is revolving around a point at a distance of #8 m#. If the object is making revolutions at a frequency of #1 Hz#, what is the centripetal force acting on the object?

1 Answer
Feb 14, 2016

Answer:

#F=momega^2r=6*(2pi)^2*8=1895# #N#.

Explanation:

In a linear frame the centripetal force is described as #F=(mv^2)/r# and in a rotational frame as #F=momega^2r# where #omega# is measured in radians.

#1# #Hz# is #2pi# #rads^-1#, so #F=6*(2pi)^2*8=1895# #N#.