An object with a mass of #6 kg# is revolving around a point at a distance of #8 m#. If the object is making revolutions at a frequency of #4 Hz#, what is the centripetal force acting on the object?

1 Answer
Mar 28, 2017

Answer:

The centripetal force is #=30319.4N#

Explanation:

The centripetal force acting on an object is

#F=mr omega^2#

The mass, #m=6kg#

The radius, #r=8m#

The angularvelocity is

#omega=4*2pi=8pi#

So

The centripetal force is

#F=6*8*(8pi)^2=30319.4N#