An object with a mass of #8 kg# is lying still on a surface and is compressing a horizontal spring by #5/6 m#. If the spring's constant is #9 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

1 Answer
Aug 28, 2017

Answer:

0,0956

Explanation:

To don't move the assemblage, the friction force must be greater than spring one.
Force of the spring=
#Fs= KX=9 kg/s^2 xx 5/6 m = 7,5 N #
from friction force =# Fa= fa xx mg # we have:
#fa = (Fa)/(mg) = (7,5 N)/(8Kg xx 9,8 m/s^2) =0,0956# that is the surface's minimum coefficient of static friction