Question

An object with a mass of `8 kg` is lying still on a surface and is compressing a horizontal spring by `5/6 m`. If the spring's constant is `9 (kg)/s^2`, what is the minimum value of the surface's coefficient of static friction?

Answer 1

0,0956

Explanation:

To don't move the assemblage, the friction force must be greater than spring one.
Force of the spring=
`Fs= KX=9 kg/s^2 xx 5/6 m = 7,5 N`
from friction force =`Fa= fa xx mg` we have:
`fa = (Fa)/(mg) = (7,5 N)/(8Kg xx 9,8 m/s^2) =0,0956` that is the surface's minimum coefficient of static friction