An object with a mass of 8 kg is lying still on a surface and is compressing a horizontal spring by 5/6 m. If the spring's constant is 9 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?

1 Answer
Aug 28, 2017

0,0956

Explanation:

To don't move the assemblage, the friction force must be greater than spring one.
Force of the spring=
Fs= KX=9 kg/s^2 xx 5/6 m = 7,5 N
from friction force = Fa= fa xx mg we have:
fa = (Fa)/(mg) = (7,5 N)/(8Kg xx 9,8 m/s^2) =0,0956 that is the surface's minimum coefficient of static friction