An object with a mass of 8 kg is lying still on a surface and is compressing a horizontal spring by 5/6 m. If the spring's constant is 9 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?

Aug 28, 2017

$F s = K X = 9 k \frac{g}{s} ^ 2 \times \frac{5}{6} m = 7 , 5 N$
from friction force =$F a = f a \times m g$ we have:
$f a = \frac{F a}{m g} = \frac{7 , 5 N}{8 K g \times 9 , 8 \frac{m}{s} ^ 2} = 0 , 0956$ that is the surface's minimum coefficient of static friction