An object with a mass of # 8 kg# is traveling in a circular path of a radius of #12 m#. If the object's angular velocity changes from # 2 Hz# to # 7 Hz# in # 6 s#, what torque was applied to the object?

1 Answer
Nov 11, 2017

Answer:

#"6031.86 Nm"# of torque was applied to object.

Explanation:

Torque is rate of change of angular momentum.

#T = (I(omega_f - ω_i))/t = (I2pi(f_f - f_i))/t = (mr^2 2pi(f_f - f_i))/t#

#T = ("8 kg × (12 m)"^2 × 2 π (7 - 2) "Hz")/"6 s" = "6031.86 Nm"#