Based on the following equation: #2 Al + 3 CuCl_2 -> 2AlCl_3 + 3 Cu#. lf 10.53 grams of #CuCl_2# were reacted, how many grams of #AlCl_3# will be produced?

1 Answer
Feb 18, 2016

Answer:

The law of equivalent proportion may help solving the problem.

Explanation:

According to this law a reactant will produce same no of equivalent of product/s as its reacting mass has.
here the equivalent mass of #CuCl_2# = Formula wt /total valency of metal(Cu) = #(63.55+2*35.55)/(1*2)# =67.33
Again
the equivalent mass of #AlCl_3# = Formula wt /total valency of metal(Al) = #(27+3*35.55)/(1*3)# =44.55
Now no. of gram equivalent in 10.53g of #CuCl_2# reacted = #10.53/67.33#=0.156
hence the same no.of gram equivalent of #AlCl_3# will be produced
So the mass of #AlCl_3# produced =0.156x equivalent mass of #AlCl_3# 0.156x44.55 = 6.95 g

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