C7H12 reacts with O2 to produce CO2 and H2O. Suppose 348 g of CO2 are produced in this reaction. What mass of O2 reacted?

1 Answer
Apr 11, 2016

Answer:

398 g

Explanation:

#C_7# #H_16# + 11 #O_2# ------> 7 C#O_2# + 8 #H_2#O

As per the chemical equation for the combustion of
Heptane , #C_7# #H_12# , for burning one mole of Heptane
eleven moles of Oxygen is needed and 7 moles of Carbon dioxide is released.

In terms of mass, 11 moles of Oxygen, ( 11 x 32 g = 352 g ) of Oxygen is needed to produce , 7 moles of Carbon Dioxide,
( 7 x 44 g = 308 g ) of Carbon dioxide is produced.

To produce 348 g of Carbon dioxide, we will need ,

= 352 g of #O_2# x 348 g of C #O_2# / 308 g of C#O_2#

= 397.7 g of #O_2#