Can anyone help me with the following question please? Thanks in advance!

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1 Answer
Mar 25, 2017

Answer:

(a) p = 0.8 atm

(b) V = 1 L

(c) # pV = 2.5 × 2 = 5.0 atm L#

(d) #pV = 2 × 2.5 = 5.0 atmL#

Explanation:

(a) Read off pressure from x-axis at volume of 5L:
enter image source here
p = 0.8 atm

(b) Read off volume from y-axis at pressure of 5 atm:
enter image source here
V = 1 L

(c) Read off pressure from graph at volume of 2 L (from question) then use Boyle's Law, #pV = #constant:
enter image source here
p = 2.5 atm
#⇒ pV = 2.5 × 2 = 5.0 atm L#

(d) I've assumed there was a typo in the question and that it should read "a pressure of 2 atm". Read off volume from graph at pressure of 2 atm (from question) then use Boyle's Law, #pV = #constant:
enter image source here
V = 2.5 L
#⇒ pV = 2 × 2.5 = 5.0 atmL#