# Can anyone help me with the following question please? Thanks in advance!

Mar 25, 2017

(a) p = 0.8 atm

(b) V = 1 L

(c)  pV = 2.5 × 2 = 5.0 atm L

(d) pV = 2 × 2.5 = 5.0 atmL

#### Explanation:

(a) Read off pressure from x-axis at volume of 5L:

p = 0.8 atm

(b) Read off volume from y-axis at pressure of 5 atm:

V = 1 L

(c) Read off pressure from graph at volume of 2 L (from question) then use Boyle's Law, $p V =$constant:

p = 2.5 atm
⇒ pV = 2.5 × 2 = 5.0 atm L

(d) I've assumed there was a typo in the question and that it should read "a pressure of 2 atm". Read off volume from graph at pressure of 2 atm (from question) then use Boyle's Law, $p V =$constant:

V = 2.5 L
⇒ pV = 2 × 2.5 = 5.0 atmL