# Can #y=2x^2 – 3x – 5# be factored? If so what are the factors ?

##### 3 Answers

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#### Explanation:

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#### Explanation:

#"for a quadratic in "color(blue)"standard form"#

#•color(white)(x)y=ax^2+bx+c color(white)(x);a!=0#

#"consider the factors of the product ac which sum to b"#

#"here "a=2,b=-3" and "c=-5#

#rArrac=2xx-5=-10" and - 5, + 2 sum to - 3"#

#color(blue)"split the middle term using these factors"#

#rArry=2x^2+2x-5x-5larrcolor(blue)"factor by grouping"#

#color(white)(y)=color(red)(2x)(x+1)color(red)(-5)(x+1)#

#"take out a "color(blue)"common factor "(x+1)#

#=(x+1)(color(red)(2x-5))#

#rArr2x^2-3x-5=(x+1)(2x-5)#

#### Answer:

#### Explanation:

Can the trinomial be factored?

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If the answer is a perfect square then you can find factors. This means you do not waste time by trying to find factors if there are none!

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