# Can #y= x^2-3x-28 # be factored? If so what are the factors ?

##### 1 Answer

#### Answer:

#### Explanation:

Luckily, your

I would like to suggest the following method:

If your factorization exists, it would look like this:

So, your goal is to find

#a + b = -3# #color(white)(i)a xx b color(white)(i) = -28#

It is always easier to start with the multiplication. Since

Possible integer pairs of

#(-4) xx 7 color(white)(xx)# or#color(white)(xx) 4 xx (-7)# #(-2) xx 14 color(white)(xii)# or#color(white)(xx)2 xx (-14)# #(-1) xx 28 color(white)(xii)# or#color(white)(xx)1 xx (-28)#

It is easy to check that the correct pair is

Thus, your factorization is

#color(white)(x)#

*By the way, this also means that the solutions for the equation*

*are #-a# and #-b#, so #x = 7# or #x = -4#.*