Can #y=x^4 + 2x^3 + 216x + 432 # be factored? If so what are the factors ?

1 Answer
Mar 16, 2018

Answer:

#color(magenta)(=(x^3+216)(x+2)#

Explanation:

Yes, #x^4+2x^3+216x+432# can be factorized in the following way :

Let's group the 1st 2 terms together & the 2nd 2 together. Then, take out the common factors.

#=x^3(x+2)+216(x+2)#

#color(magenta)(=(x^3+216)(x+2)#

~Hope this helps! :)