# Exactly 5.00 L of air at -50.0°C is warmed to 100.0°C. What is the new volume if the pressure remains constant?

Jun 12, 2016

Given your reaction conditions, your volume of gas is in a piston. The gas should expand to a $\cong 8 \cdot L$ volume.

#### Explanation:

I think you have asked this question before; it is still suspect because we must assume that the gas is enclosed in a container whose volume can change, i.e. a piston.

Charles' Law states that $\text{Volume "prop" Temperature}$, i.e. $V \propto T$, or $V = k T$.

Solving for $k$, ${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$, and here we must use $\text{ Absolute Temperature}$ $=$ ""^@C + 273.15*K.

${V}_{2} = \frac{{V}_{1} {T}_{2}}{T} _ 1$ $=$ $\frac{5.00 \cdot L \times 373.15 \cdot K}{223.15 \cdot K}$ $=$ ??L