# Factored completely, the expression 6x-x^3-x^2 is equivalent to?

$- x \left(x + 3\right) \left(x - 2\right)$
First of all, this can be factored as $- x \left({x}^{2} + x - 6\right)$.
Next, we can factor as $- x \left(x + 3\right) \left(x - 2\right)$.