Given the following profit function for a company, #p(s)=-20s^2 +1400s -12000#, if the selling price is $35 how much will the company profit? What's the difference in profit if the selling price is $20 verses $53?

1 Answer
Jun 22, 2018

Answer:

At selling price of #$35# , profit is #$12500#
At selling price of #$20 and $53# profits are
#p(20)= $8000# and #p(53)= $6020#

Explanation:

Let #s# denotes selling price , then profit function of the company

is #p(s) -20 s^2 +1400 s -12000# . When selling price is #s=$35#

then profit is #p(35)= -20*35^2 +1400*35 -12000# or

#p(35)= -20*35^2 +1400*35 -12000= $12500#

When selling price is #s=$20# , profit is

#p(20)= -20*20^2 +1400*20 -12000= $8000#

When selling price is #s=$53# , profit is

#p(53)= -20*53^2 +1400*53 -12000= $6020# [Ans]