Question

Given the functions `g(x) = (2x) (1/2)`, `f(x) = x^2 + 1` what is f(g(x))?

Answer 1

`(f@g)(x)=f(g(x))=f((2x)/2)=f(x)=x^2+1`

Explanation:

`(f@g)(x)=f(g(x))=f((2x)/2)=f(x)=x^2+1`