Question

Given the triangle with angle b= 72 degrees, B=128, and A=96, how do you use the law of Sines to solve the triangle for point c?

Answer 1

First, find A. Use the trig identity: sin A/a = sin B/b

`sin A = (a.sin B)/b = (96.(0.95))/128 = 0.71` -> A = 45.50

C = 180 - 72 - 45.50 = 62.50 deg

Find c. Trig identity: `c/sin C = a/sin A -> c = (a.sin C)/sin A` =

c = (96.(0.89))/0.71 = 120.34