How can you graph the linear equation x=y+3?

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Answer 1 · 2017-06-12T03:29:54

See the explanation.

Graph:

#x=y+3#

Solve for #y# to get the slope intercept form: #y=mx+b#, where #m# is the slope and #b# is the y-intercept.

Subtract #y# from both sides.

#-y+x=3#

Subtract #x# to both sides.

#-y=-x+3#

Multiply both sides by #-1#.

#y=x-3#

Now determine several points on the line by choosing values for #x# and solving for #y#.

#"Points"#

#x=-2,##y=-5#

#x=0,##y=-3#

#x=2,##y=-1#

Plot the points and draw a straight line through the them. graph{y=x-3 [-16.02, 16, -8.01, 8.01]}