How can you use trigonometric functions to simplify # 13 e^( ( pi)/8 i ) # into a non-exponential complex number?
1 Answer
Mar 8, 2016
Explanation:
Using
#color(blue)" Euler's relation"# which states
#re^(theta i) = r(costheta + isintheta )# here r = 13 and
#theta = pi/8 #
#rArr 13e^(pi/8 i) = 13 [ cos(pi/8) + isin(pi/8) ] #
