Question

How can you use trigonometric functions to simplify `14 e^( ( pi)/8 i )` into a non-exponential complex number?

Answer 1

The complex number is `14(cos(pi/8)+isin(pi/8))`

Explanation:

Let `z` be the complex number

So `z=14e^(ipi/8)`

We use `z=re^(itheta)=r(costheta+isintheta)`

So `r=14` and `theta=pi/8`

`z=14(cos(pi/8)+isin(pi/8))`