How can you use trigonometric functions to simplify # 8 e^( ( 5 pi)/3 i ) # into a non-exponential complex number?
1 Answer
Feb 26, 2016
Explanation:
using
#color(blue) " Euler's relation" , " which states "#
#re^(theta i) = r (costheta + isintheta ) # here r = 8 and
# theta = (5pi)/3 #
#rArr8e^((5pi)/3 i) = 8 [ cos((5pi)/3) + isin((5pi)/3) ] #
