# How do find the vertex and axis of symmetry, and intercepts for a quadratic equation y= -3x^2 + 5?

Jun 10, 2015

$y = - 3 {x}^{2} + 5$

#### Explanation:

x of vertex:$x = - \frac{b}{2} a = 0$
y of vertex: y = 5
Axis of symmetry = x of vertex = 0.
y-intercept: y = 5
x-intercepts: y = 0

$3 {x}^{2} = 5$ --> ${x}^{2} = \frac{5}{3}$--> $x = \pm \frac{\sqrt{5}}{\sqrt{3}}$