How do I change an Ax+By=C equation to a y=mx+b equation where m is the slope and b is the y intercept like 4x+2y=8?

2 Answers
Mar 21, 2018

Answer:

#y=(-A/B)x+C/A#

Explanation:

If
#color(white)("XXX")Ax+By=C#
then
after subtracting #Ax# from both sides:
#color(white)("XXX")By=-Ax+C#
then dividing both sides by #B#
#color(white)("XXX")y=(-A/B)x+C/A#
which is the slope-intercept form with
#color(white)("XXX")#slope#=(-A/B)#
and
#color(white)("XXX")#y-intercept#=(C/A)#

Mar 21, 2018

Answer:

#y=-2x+4#

Explanation:

#"Rearrange "4x+2y=8" into required form"#

#"subtract "4x" from both sides"#

#cancel(4x)cancel(-4x)+2y=-4x+8#

#rArr2y=-4x+8#

#"divide all terms by 2"#

#(cancel(2) y)/cancel(2)=(-4)/2x+8/2#

#rArry=-2x+4larrcolor(red)"in slope-intercept form"#