# How do I evaluate int_1^2(y + 5y^7)/y^3 dy?

${\int}_{1}^{2} \left[\frac{y}{y} ^ 3 + 5 {y}^{7} / {y}^{3}\right] \mathrm{dy} =$
${\int}_{1}^{2} \left[\frac{1}{y} ^ 2 + 5 {y}^{4}\right] \mathrm{dy} =$
${\int}_{1}^{2} {y}^{-} 2 \mathrm{dy} + {\int}_{1}^{2} 5 {y}^{4} \mathrm{dy} =$
$= - \frac{1}{y} {|}_{1}^{2}$ $+ 5 {y}^{5} / 5 {|}_{1}^{2} =$
$= - \frac{1}{y} {|}_{1}^{2}$ $+ {y}^{5} {|}_{1}^{2} =$
$\left(- \frac{1}{2} + 1\right) + \left({2}^{5} - 1\right) = 31.5$