Question

How do I evaluate `int_1^2(y + 5y^7)/y^3 dy`?

Answer 1

I would break down the fraction as:
`int_1^2[y/y^3+5y^7/y^3]dy=`
`int_1^2[1/y^2+5y^4]dy=`
`int_1^2y^-2dy + int_1^2 5y^4dy=`
`=-1/y|_1^2` `+ 5y^5/5|_1^2=`
`=-1/y|_1^2` `+ y^5|_1^2=`
`(-1/2+1)+(2^5-1)=31.5`