Question

How do I evaluate `int5v (v^2 + 2)^2dv`?

Answer 1

I would use a Brute Force approach, expanding the square, multiplying by `5v` and integrating:
`int5v(v^2+2)^2dv=int5v(v^4+4v^2+4)dv=`
`int(5v^5+20v^3+20v)dv=5v^6/6+20v^4/4+20v^2/2+c=`
`=5/6v^6+5v^4+10v^2+c`

Remember that `intx^ndx=x^(n+1)/(n+1)+c`