# How do I find the vertex of the function -6(x-3)^2 -5?

Oct 4, 2016

vertex$\to \left(x , y\right) = \left(3 , - 5\right)$

#### Explanation:

This is what they call the vertex form of a quadratic.

Set as$\text{ } y = - 6 {\left(x \textcolor{red}{- 3}\right)}^{2} \textcolor{g r e e n}{- 5}$

From this x-vertex $= \left(- 1\right) \times \textcolor{red}{- 3} = + 3$
From this y-vertex $= \textcolor{g r e e n}{- 5}$

So vertex$\to \left(x , y\right) = \left(3 , - 5\right)$