# How do I graph #-9x^2+25y^2+36x+150y-36=0# algebraically?

##### 1 Answer

Mar 26, 2015

You now have an equation of a hyperbola with vertex at

Asymptotes:

The graph of the function:

graph{(y+3)^2/9 -(x-2)^2/25 = 1 [-10, 10, -5, 5]}