# How do you sketch the graph of #x^2+y^2+8x-6y+16=0#?

##### 1 Answer

Feb 18, 2015

Hello,

Use canonical form :

Indeed, you have

Same thing with

So, your equation has a good looking form :

or better :

You recognize the circle of center

graph{(x+4)^2+(y-3)^2=9 [-13.87, 6.13, -2.22, 7.78]}