How do I graph $(x+2)^2/9+(y-3)^2/25=1$ algebraically?

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Answer 1 · 2014-10-08T16:47:10

You have an ellipse in the form

$(x - h)^2/b^2 + (y - k)^2/a^2 = 1$

where (h, k) is the ellipse's center.
You have $(-2, 3)$ as your center.

$a$ is under $y$ . That means your major axis is vertical with length $2a = 10$ .
The endpoints of your major axis are $(-2, -2)$ and $(-2, 8)$

Meanwhile, the minor axis is horizontal with length $2b = 6$
The endpoints of your major axis are $(-5, 3)$ and $(1, 3)$

Connect the endpoints of your major and minor axis and you have your ellipse

How do I graph (x+2)^2/9+(y-3)^2/25=1(x+2)^2/9+(y-3)^2/25=1 algebraically?