How do I use the quadratic formula to solve $x^2+8x=-2$ ?

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Answer 1 · 2014-09-30T03:26:34

$ax^2+bx+c=0$

$x^2+8x=-2$

$x^2+8x+2=0$

$a=1, b=8, c=2$

Quadratic formula

$x=(-(8)+-sqrt((8)^2-4(1)(2)))/(2(1))$

$x=(-8+-sqrt(64-8))/2$

$x=(-5+-sqrt(56))/2$

$x=(-5+-sqrt(2*2*2*7))/2$

$x=(-5+-(2)*sqrt(2*7))/2$

$x=(-5+-(2)*sqrt(14))/2$

$x=(-5+-2sqrt(14))/2$

How do I use the quadratic formula to solve x^2+8x=-2x^2+8x=-2?