# How do I use the vertex formula to determine the vertex of the graph for x^2 - 2x + 44y + 353 = 0 ?

Jun 24, 2015

Vertex is (1, -8)

#### Explanation:

To write the equation in the vertex form write it as 44y= $- {x}^{2}$+2x-353. Now complete the square of x terms 44y= $- {x}^{2}$+2x-1+1-353

44y= -${\left(x - 1\right)}^{2}$ -352

y= $- \frac{1}{44} {\left(x - 1\right)}^{2} - \frac{352}{44}$= $- \frac{1}{44} {\left(x - 1\right)}^{2} - 8$

Vertex is therefore (1, -8)