Question

How do I use the vertex formula to determine the vertex of the graph for `x^2 - 2x + 44y + 353 = 0`?

Answer 1

Vertex is (1, -8)

Explanation:

To write the equation in the vertex form write it as 44y= `-x^2`+2x-353. Now complete the square of x terms 44y= `-x^2`+2x-1+1-353

44y= -`(x-1)^2` -352

y= `-1/44 (x-1)^2 -352/44`= `-1/44(x-1)^2 -8`

Vertex is therefore (1, -8)