# How do yo write the orbital diagram for silver?

Aug 12, 2018

Well, we can write the electronic configuration of the silver atom...

#### Explanation:

A quick glance at the Periodic Table tells us that ${Z}_{\text{Ag}} = 47$..and so for the NEUTRAL atom....

We use the Aufbau process to write the electronic distribution of the SILVER atom...

${\underbrace{1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 3 {d}^{10} 4 {s}^{2} 4 {p}^{6}}}_{\text{electronic configuration of krypton}} 5 {s}^{1} 4 {d}^{10}$

That the configuration shows $5 {s}^{1} 4 {d}^{10}$ RATHER than $5 {s}^{2} 4 {d}^{9}$ is POSSIBLY a result of Hund's rule...