How do you add $(- 2 + 8 i) + (5 + 3 i)$ $(-2+8i)+(5+3i)$ in trigonometric form?

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Answer 1 · 2017-10-21T17:20:13

$3 + 11 i$ $3+11i$

We can just simply expend the expression and group the like terms together as the following:

$(- 2 + 8 i) + (5 + 3 i)$ $(-2+8i)+(5+3i)$
$= - 2 + 8 i + 5 + 3 i$ $=-2+8i+5+3i$
$= (- 2 + 5) + (8 i + 3 i)$ $=(-2+5)+(8i+3i)$
$= 3 + 11 i$ $=3+11i$

It's the answer! Hope it can help you :)

How do you add (−2+8i)+(5+3i)(-2+8i)+(5+3i) in trigonometric form?