# How do you add (6-4i) and (8-2i) in trigonometric form?

Mar 9, 2018

$\left(6 - 4 i\right) + \left(8 - 2 i\right) = 14 - 6 i$

#### Explanation:

Although we could convert each term into polar form then perform the addition it would be futile to do so, as we can can just perform elementary arithmetic on the expression to simplify it:

Thus:

$\left(6 - 4 i\right) + \left(8 - 2 i\right) = \left(6 + 8\right) + \left(- 4 - 2\right) i$
$\text{ } = 14 - 6 i$