# What volume of water would be added to 16.5 mL of a 0.0813 M solution of sodium borate in order to get a 0.0200 M solution?

To solve this we'll need to apply the equation

${M}_{1} {V}_{1} = {M}_{2} {V}_{2}$

${V}_{1} = 16.5 m l$
V_2 = ?
${M}_{1} = 0.0813$
${M}_{2} = 0.200$

Solve the equation for V2
${V}_{2}$ = $\frac{{M}_{1} {V}_{1}}{M} _ 2$

${V}_{2}$ = (0.0813M . 16.5ml) / (0.0200M = $67.1 m l$

Please note the question asks you to find the volume that must be added. You'll need to subtract 16.5mL from 67.1 to find the answer of
50.6mL.

Here is a video which discusses how to perform dilution calculations.