How do you calculate #cos(tan^-1(4/3)-sin^-1(12/13))#?
The restriction for the range of
We need to draw two triangles. They will both be in quadrant I since both the arguments are positive. Let's call the first one triangle A and the second one triangle B.
For triangle A the opposite is 4 and adjacent is 3 so the hypotenuse is 5. For triangle B the opposite is 12 and the hypotenuse is 13 so the adjacent is 5. Now
Use the formula