How do you calculate #sin^-1(sin2)#?
Inverses cancel each other out.
#color(blue)(arcsin(sin(2^@)) = 2^@)#
#arcsin(sin(2 cancel"rad" xx 180^@/(pi cancel"rad"))) = arcsin[sin((360/pi)^@)]#
#color(blue)(arcsin(sin("2 rad")) = pi - 2 " rad")#.
Note that this is NOT:
which is not the same thing. If you did have
However, even though
Refer to the Explanation Section.
Recall the following Defn. of
Substituting the value
the L.H.S., we get,
Now, regarding the Soln. of the Problem, we note that, there is
no mention about the Measure of the Angle
not clear, it is
If it is
In case, it is