# How do you calculate #sin^-1(sin2)#?

##### 2 Answers

**Inverses** cancel each other out.

Note that

#color(blue)(arcsin(sin(2^@)) = 2^@)#

If the

#arcsin(sin(2 cancel"rad" xx 180^@/(pi cancel"rad"))) = arcsin[sin((360/pi)^@)]#

#= arcsin(sin(114.59^@))#

The

#color(blue)(arcsin(sin("2 rad")) = pi - 2 " rad")# .

Note that this is NOT:

#1/(sin(sin2))#

which is not the same thing. If you did have

However, even though

Refer to the **Explanation Section.**

#### Explanation:

Recall the following **Defn.** of

Substituting the value **R.H.S.,** into

the **L.H.S.,** we get,

Now, regarding the **Soln.** of the **Problem,** we note that, there is

**no** mention about the **Measure** of the **Angle**

**not clear,** it is

If it is

In case, it is

where, since