How do you calculate # (tan^-1 (1)) #?

1 Answer
A. S. Adikesavan
May 18, 2016

If a = tan^(-1)1, a has just one value #pi/4 in [0, pi]#. There are two values #pi/4 and (5pi)/4 in [0. 2pi]# and #npi+pi/4, n=0, +-1, +-2, .. in (-oo, +oo)#..

Explanation:

If a = tan^(-1)1 and if the range for a is not specified,

#a = npi+pi/4, n=0, +-1, +-2, .. in (-oo, +oo)#.

n=0 gives #pi/4 in [0. pi]#

n=0, 1 give #a=pi/4, (5pi)/4 in [0, 2pi] #..

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