# How do you calculate  [tan^-1((1/2))]?

${26}^{\circ} 57 + k {180}^{\circ}$
Find $\arctan \left(\frac{1}{2}\right)$.
$\tan x = \frac{1}{2}$ --> arc $x = {26}^{\circ} 57 + k {180}^{\circ}$