How do you calculate the amount of heat (in kJ) required to heat 4.14 kg of water from 21.50 C to 33.85 C.?

1 Answer
Nov 29, 2016


You need the specific heat of water, which is widely listed in data books and the public doman.


You need the specific heat of water which is 4.2 #(kJ)/(kg.K)#.

Then you can use the relationship #E = m.c.theta# where #E# is the heat energy involved, #m# is the mass of the substance being heated, and #theta# is the temperature change.

The temperature change here is 4.14 x 4.2 x 12.35 = 214.74 kJ.