How do you calculate the amount of heat (in kJ) required to heat 4.14 kg of water from 21.50 C to 33.85 C.?
You need the specific heat of water, which is widely listed in data books and the public doman.
You need the specific heat of water which is 4.2
Then you can use the relationship
The temperature change here is 4.14 x 4.2 x 12.35 = 214.74 kJ.