# How do you calculate the amount of heat (in kJ) required to heat 4.14 kg of water from 21.50 C to 33.85 C.?

##### 1 Answer

Nov 29, 2016

You need the specific heat of water, which is widely listed in data books and the public doman.

#### Explanation:

You need the specific heat of water which is 4.2

Then you can use the relationship

The temperature change here is 4.14 x 4.2 x 12.35 = 214.74 kJ.