How do you calculate the amount of heat (in kJ) required to heat 4.14 kg of water from 21.50 C to 33.85 C.?
1 Answer
Nov 29, 2016
You need the specific heat of water, which is widely listed in data books and the public doman.
Explanation:
You need the specific heat of water which is 4.2
Then you can use the relationship
The temperature change here is 4.14 x 4.2 x 12.35 = 214.74 kJ.