How do you calculate the amount of heat (in kJ) required to heat 4.14 kg of water from 21.50 C to 33.85 C.?

1 Answer
Nov 29, 2016

Answer:

You need the specific heat of water, which is widely listed in data books and the public doman.

Explanation:

You need the specific heat of water which is 4.2 #(kJ)/(kg.K)#.

Then you can use the relationship #E = m.c.theta# where #E# is the heat energy involved, #m# is the mass of the substance being heated, and #theta# is the temperature change.

The temperature change here is 4.14 x 4.2 x 12.35 = 214.74 kJ.