# How do you calculate the inverse csc (-7/3)?

Let ${\csc}^{-} 1 \left(- \frac{7}{3}\right) = x$
$\csc x = - \frac{7}{3}$
$\sin x = - \frac{3}{7} \to \sin \left(- x\right) = \frac{3}{7} \to - x = {\sin}^{-} 1 \left(\frac{3}{7}\right) = 25.37 \mathrm{de} g r e e s$.