How do you calculate the pressure in atmospheres of 1.00 mol of argon in a .500-L container at 29.0°C?

$P \cong 50 \cdot a t m$
We use the Ideal Gas Equation.........$P = \frac{n R T}{V}$
(1.00*cancel(mol)xx0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx302*cancelK)/(0.500*cancelL)=??*atm