How do you calculate the #tan^-1(sqrt3/3)#?

1 Answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

3
mason m Share
Jun 12, 2018

Answer:

#pi/6#

Explanation:

Another way of asking this question is: "the tangent of what angle gives me #sqrt3/3#?"

We know that #" "tan(pi/6)=sqrt3/3#.

So then, #" "" "tan^-1(sqrt3/3)=pi/6#


Note that even though tangent is positive in the third quadrant, and that the tangent of an infinite amount of coterminal angles is #sqrt3/3#, we need to observe that the range of #tan^-1(x)# is #(-pi/2,pi/2)#, so only #pi/6# is a valid answer within this range.

Was this helpful? Let the contributor know!
1500
Trending questions
Impact of this question
5649 views around the world
You can reuse this answer
Creative Commons License