How do you change the polar equation #r(4sintheta-costheta)=1# into rectangular form?

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Answer 1 · 2016-09-29T10:03:53

#4y-x=1#

If polar coordinates are #(r,theta)# nd rectangular or Cartesian coordinates are #(x,y)#, the relation between the two is given by

#x=rcostheta# and #y=rsintheta#

Hence #r(4sintheta-costheta)=1#

#hArr4rsintheta-rcostheta=1#

or #4y-x=1#

Answer 2 · 2016-09-29T10:06:49

#4y-x=1#

With the pass equations

#{(x=rcostheta),(y=rsintheta):}#

#r(4y/r-x/r)=1-> 4y-x = 1# so

#4y-x=1#