How do you classify # x^2 + 2y^2 = 2#? Precalculus Geometry of a Hyperbola Graphing Hyperbolas 1 Answer BeeFree Oct 6, 2015 This is an ellipse. Explanation: Since the coefficients on #x^2# and #y^2# are not equal, but positive this will be an ellipse. Answer link Related questions How do I graph the hyperbola with the equation #4x^2−y^2+4y−20=0?#? How do I graph the hyperbola with the equation #4x^2−25y^2−50y−125=0#? How do I graph the hyperbola with the equation #4x^2−y^2−16x−2y+11=0=0#? How do I graph #(x-1)^2/4-(y+2)^2/9=1# on a TI-84? Where should I draw the asymptotes of #(x+2)^2/4-(y+1)^2/16=1#? How do I graph the hyperbola represented by #(x-2)^2/16-y^2/4=1#? How do I find an equation for a hyperbola, given its graph? How do I graph the hyperbola represented by #4x^2-y^2-16x-2y+11=0#? What information do you need to graph hyperbolas? How do you find the center of the hyperbola, its focal length, and its eccentricity if a... See all questions in Graphing Hyperbolas Impact of this question 1549 views around the world You can reuse this answer Creative Commons License