# How do you classify x^2 + y^2 = 16?

Apr 2, 2018

It is a circle with centre (0,0) and radius equal to 4

#### Explanation:

${x}^{2} + {y}^{2} = 16$
is in the form ${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$
ie ${\left(x - 0\right)}^{2} + {\left(y - o\right)}^{2} = {4}^{2}$