How do you completely factor $x^3 + 4x^2 - 45x$ ?

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Answer 1 · 2018-06-12T21:54:02

$x(x-5)(x+9)$

take the $x$ as a common factor such that:

$x(x^{2}+4x-45)$

factorize the expression inside the brackets

$x(x^{2} + 9x-5x-45)$

$x(x(x+9)-5(x+9))$
$x(x-5)(x+9)$

How do you completely factor x^3 + 4x^2 - 45xx^3 + 4x^2 - 45x?