How do you convert #(0, 8)# to polar form?

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Answer 1 · 2016-05-03T09:06:56

Polar coordinates for Cartesian coordinates #(0,8)# are #(8,pi/2)#

If #(x,y)# in Cartesian form and #(r,theta)# is in polar form the relation between them is as follows:

#x=rcostheta#, #y=rsintheta#, #r^2=x^2+y^2# and #tantheta=y/x#

Here #x=0# and #y=8#, hence

#r^2=0^2+8^2=0+64=64# or #r=8#

#costheta=0/8=0# and #sintheta=8/8=1#

Hence #theta=pi/2#

Hence polar coordinates for Cartesian coordinates #(0,8)# are #(8,pi/2)#