How do you convert #4 (sqrt(3) +i)# to polar form? Trigonometry The Polar System The Trigonometric Form of Complex Numbers 1 Answer A. S. Adikesavan Apr 18, 2016 #8 e^(i(pi/3))=8 ( cos (pi/6) + i sin (pi/6))# Explanation: #x=4sqrt3=y# #x+ i y = r ( cos theta + i sin theta )# #r=sqrt(x^2+y^2)=8# #cos theta = x/r = sqrt3/2, sin theta = y/r=1/2#, Both are positive. #theta# is in the 1st quadrant. #theta=pi/6# So, #4( sqrt3 + i )=8 (cos pi/6 + i sin pi/6 )# Answer link Related questions What is The Trigonometric Form of Complex Numbers? How do you find the trigonometric form of the complex number 3i? How do you find the trigonometric form of a complex number? What is the relationship between the rectangular form of complex numbers and their corresponding... How do you convert complex numbers from standard form to polar form and vice versa? How do you graph #-3.12 - 4.64i#? Is it possible to perform basic operations on complex numbers in polar form? What is the polar form of #-2 + 9i#? How do you show that #e^(-ix)=cosx-isinx#? What is #2(cos330+isin330)#? See all questions in The Trigonometric Form of Complex Numbers Impact of this question 2341 views around the world You can reuse this answer Creative Commons License