# How do you convert 5.0g of nitrogen dioxide (NO_2) to grams of ozone gas (O_3)?

##### 1 Answer
Feb 11, 2017

With difficulty........we would get $3.5 \cdot g$ of ozone........

#### Explanation:

Well, first we need a stoichiometric equation:

$3 N {O}_{2} \left(g\right) \rightarrow 2 {O}_{3} \left(g\right) + {N}_{2} \left(g\right)$

Please let me say that I do not know whether this reaction could be reliably accomplished. Certainly, we could assess the energy transfer of the reaction.

Given the equation, we see that 2 equiv of ozone derives from 3 equiv of nitric oxide:

$\text{Moles of}$ $N {O}_{2}$ $=$ $\frac{5.0 \cdot g}{46.01 \cdot g \cdot m o {l}^{-} 1} = 0.109 \cdot m o l .$

And thus with quantitative reaction we would get:

$\frac{2}{3} \times 0.109 \cdot m o l \times 48.00 \cdot g \cdot m o {l}^{-} 1 = 3.49 \cdot g$ $\text{ozone gas}$.